Base | Representation |
---|---|
bin | 101100010011001111… |
… | …0000000100100100101 |
3 | 100002120002200112210211 |
4 | 1120212132000210211 |
5 | 3024313434301011 |
6 | 111412042215421 |
7 | 6605345310055 |
oct | 1304636004445 |
9 | 302502615724 |
10 | 95134681381 |
11 | 3738a058223 |
12 | 165304b4571 |
13 | 8c8184839c |
14 | 4866c1b565 |
15 | 271c038b21 |
hex | 1626780925 |
95134681381 has 2 divisors, whose sum is σ = 95134681382. Its totient is φ = 95134681380.
The previous prime is 95134681363. The next prime is 95134681399. The reversal of 95134681381 is 18318643159.
It is a balanced prime because it is at equal distance from previous prime (95134681363) and next prime (95134681399).
It can be written as a sum of positive squares in only one way, i.e., 94009078881 + 1125602500 = 306609^2 + 33550^2 .
It is an emirp because it is prime and its reverse (18318643159) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 95134681381 - 231 = 92987197733 is a prime.
It is a super-2 number, since 2×951346813812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (95134681351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47567340690 + 47567340691.
It is an arithmetic number, because the mean of its divisors is an integer number (47567340691).
Almost surely, 295134681381 is an apocalyptic number.
It is an amenable number.
95134681381 is a deficient number, since it is larger than the sum of its proper divisors (1).
95134681381 is an equidigital number, since it uses as much as digits as its factorization.
95134681381 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 622080, while the sum is 49.
The spelling of 95134681381 in words is "ninety-five billion, one hundred thirty-four million, six hundred eighty-one thousand, three hundred eighty-one".
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