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95201231 is a prime number
BaseRepresentation
bin1011010110010…
…10011111001111
320122010201112112
411223022133033
5143332414411
613240254235
72234124416
oct553123717
9218121475
1095201231
1149814104
1227a7137b
13169534b8
14c90247d
158557b8b
hex5aca7cf

95201231 has 2 divisors, whose sum is σ = 95201232. Its totient is φ = 95201230.

The previous prime is 95201203. The next prime is 95201233. The reversal of 95201231 is 13210259.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 95201231 - 214 = 95184847 is a prime.

It is a super-2 number, since 2×952012312 = 18126548767830722, which contains 22 as substring.

Together with 95201233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 95201197 and 95201206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95201233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47600615 + 47600616.

It is an arithmetic number, because the mean of its divisors is an integer number (47600616).

Almost surely, 295201231 is an apocalyptic number.

95201231 is a deficient number, since it is larger than the sum of its proper divisors (1).

95201231 is an equidigital number, since it uses as much as digits as its factorization.

95201231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

The square root of 95201231 is about 9757.1118165162. Note that the first 3 decimals coincide. The cubic root of 95201231 is about 456.6122108745.

The spelling of 95201231 in words is "ninety-five million, two hundred one thousand, two hundred thirty-one".