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953540051 is a prime number
BaseRepresentation
bin111000110101011…
…101110111010011
32110110020212001012
4320311131313103
53423101240201
6234341401135
732425646102
oct7065356723
92413225035
10953540051
1144a280832
122274091ab
131227211a9
14908d6039
1558aa55bb
hex38d5ddd3

953540051 has 2 divisors, whose sum is σ = 953540052. Its totient is φ = 953540050.

The previous prime is 953540041. The next prime is 953540053. The reversal of 953540051 is 150045359.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-953540051 is a prime.

It is a super-2 number, since 2×9535400512 = 1818477257722165202, which contains 22 as substring.

Together with 953540053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (953540053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 476770025 + 476770026.

It is an arithmetic number, because the mean of its divisors is an integer number (476770026).

Almost surely, 2953540051 is an apocalyptic number.

953540051 is a deficient number, since it is larger than the sum of its proper divisors (1).

953540051 is an equidigital number, since it uses as much as digits as its factorization.

953540051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 32.

The square root of 953540051 is about 30879.4438259500. The cubic root of 953540051 is about 984.2671250642.

The spelling of 953540051 in words is "nine hundred fifty-three million, five hundred forty thousand, fifty-one".