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954010105513 is a prime number
BaseRepresentation
bin11011110000111110110…
…11101111011010101001
310101012110121022201110121
431320133123233122221
5111112303041334023
62010133255243241
7125632155046003
oct15703733573251
93335417281417
10954010105513
11338658919533
12134a88079521
136bc6927811a
143426253b373
1519c38e90d5d
hexde1f6ef6a9

954010105513 has 2 divisors, whose sum is σ = 954010105514. Its totient is φ = 954010105512.

The previous prime is 954010105511. The next prime is 954010105537. The reversal of 954010105513 is 315501010459.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 537659962009 + 416350143504 = 733253^2 + 645252^2 .

It is a cyclic number.

It is not a de Polignac number, because 954010105513 - 21 = 954010105511 is a prime.

Together with 954010105511, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (954010105511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 477005052756 + 477005052757.

It is an arithmetic number, because the mean of its divisors is an integer number (477005052757).

Almost surely, 2954010105513 is an apocalyptic number.

It is an amenable number.

954010105513 is a deficient number, since it is larger than the sum of its proper divisors (1).

954010105513 is an equidigital number, since it uses as much as digits as its factorization.

954010105513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 34.

The spelling of 954010105513 in words is "nine hundred fifty-four billion, ten million, one hundred five thousand, five hundred thirteen".