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9543701113 is a prime number
BaseRepresentation
bin10001110001101100…
…10101001001111001
3220122010011020201121
420320312111021321
5124021141413423
64215002345241
7455334056332
oct107066251171
926563136647
109543701113
1140581969a1
121a241bb221
13b912c672b
14667705289
153accc845d
hex238d95279

9543701113 has 2 divisors, whose sum is σ = 9543701114. Its totient is φ = 9543701112.

The previous prime is 9543701107. The next prime is 9543701117. The reversal of 9543701113 is 3111073459.

It is a happy number.

9543701113 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5857147024 + 3686554089 = 76532^2 + 60717^2 .

It is a cyclic number.

It is not a de Polignac number, because 9543701113 - 221 = 9541603961 is a prime.

It is not a weakly prime, because it can be changed into another prime (9543701117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4771850556 + 4771850557.

It is an arithmetic number, because the mean of its divisors is an integer number (4771850557).

Almost surely, 29543701113 is an apocalyptic number.

It is an amenable number.

9543701113 is a deficient number, since it is larger than the sum of its proper divisors (1).

9543701113 is an equidigital number, since it uses as much as digits as its factorization.

9543701113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11340, while the sum is 34.

The square root of 9543701113 is about 97691.8682030393. The cubic root of 9543701113 is about 2121.1543725731.

The spelling of 9543701113 in words is "nine billion, five hundred forty-three million, seven hundred one thousand, one hundred thirteen".