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954544145713 is a prime number
BaseRepresentation
bin11011110001111110100…
…00111100010100110001
310101020211211012202220021
431320333100330110301
5111114401300130323
62010302253443441
7125651331236344
oct15707720742461
93336754182807
10954544145713
11338902315874
12134bb6aa0581
136c022abb142
14342b343445b
1519c6acd005d
hexde3f43c531

954544145713 has 2 divisors, whose sum is σ = 954544145714. Its totient is φ = 954544145712.

The previous prime is 954544145707. The next prime is 954544145719. The reversal of 954544145713 is 317541445459.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (954544145707) and next prime (954544145719).

It can be written as a sum of positive squares in only one way, i.e., 950170704289 + 4373441424 = 974767^2 + 66132^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-954544145713 is a prime.

It is a super-2 number, since 2×9545441457132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (954544145719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 477272072856 + 477272072857.

It is an arithmetic number, because the mean of its divisors is an integer number (477272072857).

Almost surely, 2954544145713 is an apocalyptic number.

It is an amenable number.

954544145713 is a deficient number, since it is larger than the sum of its proper divisors (1).

954544145713 is an equidigital number, since it uses as much as digits as its factorization.

954544145713 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6048000, while the sum is 52.

The spelling of 954544145713 in words is "nine hundred fifty-four billion, five hundred forty-four million, one hundred forty-five thousand, seven hundred thirteen".