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95993784013 is a prime number
BaseRepresentation
bin101100101100110101…
…1001110011011001101
3100011202222020111001211
41121121223032123031
53033043402042023
6112033211534421
76635546462341
oct1313153163315
9304688214054
1095993784013
113778aa967a6
121673015a411
13908a82293a
144908d6d621
15276c687a0d
hex1659ace6cd

95993784013 has 2 divisors, whose sum is σ = 95993784014. Its totient is φ = 95993784012.

The previous prime is 95993784011. The next prime is 95993784023. The reversal of 95993784013 is 31048739959.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59490624649 + 36503159364 = 243907^2 + 191058^2 .

It is an emirp because it is prime and its reverse (31048739959) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 95993784013 - 21 = 95993784011 is a prime.

Together with 95993784011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95993784011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47996892006 + 47996892007.

It is an arithmetic number, because the mean of its divisors is an integer number (47996892007).

Almost surely, 295993784013 is an apocalyptic number.

It is an amenable number.

95993784013 is a deficient number, since it is larger than the sum of its proper divisors (1).

95993784013 is an equidigital number, since it uses as much as digits as its factorization.

95993784013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7348320, while the sum is 58.

The spelling of 95993784013 in words is "ninety-five billion, nine hundred ninety-three million, seven hundred eighty-four thousand, thirteen".