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96330414773 is a prime number
BaseRepresentation
bin101100110110110111…
…1010111101010110101
3100012122102200002122202
41121231233113222311
53034241041233043
6112130435034245
76650105005205
oct1315557275265
9305572602582
1096330414773
113794300a43a
1216804a3b985
1391124a7838
14493b95a405
15278bed01b8
hex166dbd7ab5

96330414773 has 2 divisors, whose sum is σ = 96330414774. Its totient is φ = 96330414772.

The previous prime is 96330414767. The next prime is 96330414787. The reversal of 96330414773 is 37741403369.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72661515364 + 23668899409 = 269558^2 + 153847^2 .

It is a cyclic number.

It is not a de Polignac number, because 96330414773 - 28 = 96330414517 is a prime.

It is a super-4 number, since 4×963304147734 (a number of 45 digits) contains 4444 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (96330414793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48165207386 + 48165207387.

It is an arithmetic number, because the mean of its divisors is an integer number (48165207387).

Almost surely, 296330414773 is an apocalyptic number.

It is an amenable number.

96330414773 is a deficient number, since it is larger than the sum of its proper divisors (1).

96330414773 is an equidigital number, since it uses as much as digits as its factorization.

96330414773 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1143072, while the sum is 47.

The spelling of 96330414773 in words is "ninety-six billion, three hundred thirty million, four hundred fourteen thousand, seven hundred seventy-three".