Base | Representation |
---|---|
bin | 10101111011000010000010… |
… | …000011100100000001111111 |
3 | 110122101020112111002020202021 |
4 | 111323002002003210001333 |
5 | 100114133131101121303 |
6 | 541020415130541011 |
7 | 26210540433340435 |
oct | 2573020203440177 |
9 | 418336474066667 |
10 | 96415607832703 |
11 | 287a26a20876a5 |
12 | a991ba7b97767 |
13 | 41a4c50413713 |
14 | 19b477c8c0d55 |
15 | b22ed058aebd |
hex | 57b0820e407f |
96415607832703 has 2 divisors, whose sum is σ = 96415607832704. Its totient is φ = 96415607832702.
The previous prime is 96415607832673. The next prime is 96415607832749. The reversal of 96415607832703 is 30723870651469.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 96415607832703 - 213 = 96415607824511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (96415607836703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48207803916351 + 48207803916352.
It is an arithmetic number, because the mean of its divisors is an integer number (48207803916352).
It is a 1-persistent number, because it is pandigital, but 2⋅96415607832703 = 192831215665406 is not.
Almost surely, 296415607832703 is an apocalyptic number.
96415607832703 is a deficient number, since it is larger than the sum of its proper divisors (1).
96415607832703 is an equidigital number, since it uses as much as digits as its factorization.
96415607832703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45722880, while the sum is 61.
The spelling of 96415607832703 in words is "ninety-six trillion, four hundred fifteen billion, six hundred seven million, eight hundred thirty-two thousand, seven hundred three".
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