Base | Representation |
---|---|
bin | 10110000101001001101101… |
… | …011111000011011110111111 |
3 | 110201211201120212100200010001 |
4 | 112011021231133003132333 |
5 | 100212031411114413324 |
6 | 542312111014455131 |
7 | 26312020166316565 |
oct | 2605115537033677 |
9 | 421751525320101 |
10 | 97111047419839 |
11 | 28a40622652642 |
12 | aa849313644a7 |
13 | 42256bcb13cbb |
14 | 19da2b2271a35 |
15 | b361340bee44 |
hex | 58526d7c37bf |
97111047419839 has 2 divisors, whose sum is σ = 97111047419840. Its totient is φ = 97111047419838.
The previous prime is 97111047419833. The next prime is 97111047419857. The reversal of 97111047419839 is 93891474011179.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-97111047419839 is a prime.
It is a super-3 number, since 3×971110474198393 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (97111047419833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48555523709919 + 48555523709920.
It is an arithmetic number, because the mean of its divisors is an integer number (48555523709920).
Almost surely, 297111047419839 is an apocalyptic number.
97111047419839 is a deficient number, since it is larger than the sum of its proper divisors (1).
97111047419839 is an equidigital number, since it uses as much as digits as its factorization.
97111047419839 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13716864, while the sum is 64.
The spelling of 97111047419839 in words is "ninety-seven trillion, one hundred eleven billion, forty-seven million, four hundred nineteen thousand, eight hundred thirty-nine".
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