Base | Representation |
---|---|
bin | 101101010000100111… |
… | …0011001001011100001 |
3 | 100021212122000012020222 |
4 | 1122201032121023201 |
5 | 3043023202413231 |
6 | 112352252412425 |
7 | 10010363642063 |
oct | 1324116311341 |
9 | 307778005228 |
10 | 97194185441 |
11 | 382466470a1 |
12 | 16a06177115 |
13 | 921c427a42 |
14 | 49c0565733 |
15 | 27dcc5227b |
hex | 16a13992e1 |
97194185441 has 2 divisors, whose sum is σ = 97194185442. Its totient is φ = 97194185440.
The previous prime is 97194185437. The next prime is 97194185443. The reversal of 97194185441 is 14458149179.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 90087021025 + 7107164416 = 300145^2 + 84304^2 .
It is a cyclic number.
It is not a de Polignac number, because 97194185441 - 22 = 97194185437 is a prime.
Together with 97194185443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (97194185443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48597092720 + 48597092721.
It is an arithmetic number, because the mean of its divisors is an integer number (48597092721).
Almost surely, 297194185441 is an apocalyptic number.
It is an amenable number.
97194185441 is a deficient number, since it is larger than the sum of its proper divisors (1).
97194185441 is an equidigital number, since it uses as much as digits as its factorization.
97194185441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1451520, while the sum is 53.
The spelling of 97194185441 in words is "ninety-seven billion, one hundred ninety-four million, one hundred eighty-five thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •