Base | Representation |
---|---|
bin | 11100100011011100111… |
… | …00000101110110001111 |
3 | 10110210101220220100122122 |
4 | 32101232130011312033 |
5 | 112033300440314411 |
6 | 2030414045403155 |
7 | 130611464212154 |
oct | 16215634056617 |
9 | 3423356810578 |
10 | 981105401231 |
11 | 3490a247020a |
12 | 13a18a2694bb |
13 | 71696913197 |
14 | 356b2ca822b |
15 | 1a7c2a9b9db |
hex | e46e705d8f |
981105401231 has 2 divisors, whose sum is σ = 981105401232. Its totient is φ = 981105401230.
The previous prime is 981105401093. The next prime is 981105401267. The reversal of 981105401231 is 132104501189.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 981105401231 - 218 = 981105139087 is a prime.
It is a super-2 number, since 2×9811054012312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 981105401191 and 981105401200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (981105401291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490552700615 + 490552700616.
It is an arithmetic number, because the mean of its divisors is an integer number (490552700616).
Almost surely, 2981105401231 is an apocalyptic number.
981105401231 is a deficient number, since it is larger than the sum of its proper divisors (1).
981105401231 is an equidigital number, since it uses as much as digits as its factorization.
981105401231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 35.
The spelling of 981105401231 in words is "nine hundred eighty-one billion, one hundred five million, four hundred one thousand, two hundred thirty-one".
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