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98131230002317 is a prime number
BaseRepresentation
bin10110010011111111110101…
…000110110000110010001101
3110212110020212010212111220211
4112103333311012300302031
5100330240224340033232
6544412510440042421
726445514234225141
oct2623776506606215
9425406763774824
1098131230002317
11292a4248073466
12b00a5a6463411
13429a973553925
141a33810d2b221
15b5294261aa47
hex593ff51b0c8d

98131230002317 has 2 divisors, whose sum is σ = 98131230002318. Its totient is φ = 98131230002316.

The previous prime is 98131230002303. The next prime is 98131230002417. The reversal of 98131230002317 is 71320003213189.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98015761884681 + 115468117636 = 9900291^2 + 339806^2 .

It is a cyclic number.

It is not a de Polignac number, because 98131230002317 - 223 = 98131221613709 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 98131230002317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (98131230002417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49065615001158 + 49065615001159.

It is an arithmetic number, because the mean of its divisors is an integer number (49065615001159).

Almost surely, 298131230002317 is an apocalyptic number.

It is an amenable number.

98131230002317 is a deficient number, since it is larger than the sum of its proper divisors (1).

98131230002317 is an equidigital number, since it uses as much as digits as its factorization.

98131230002317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 40.

The spelling of 98131230002317 in words is "ninety-eight trillion, one hundred thirty-one billion, two hundred thirty million, two thousand, three hundred seventeen".