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98942164703 is a prime number
BaseRepresentation
bin101110000100101101…
…0011001111011011111
3100110101110010202000122
41130021122121323133
53110113143232303
6113241533545155
710101610344404
oct1341132317337
9313343122018
1098942164703
1138a632aa858
12172136451bb
13943a6029b5
144b0877a2ab
152891431e38
hex1709699edf

98942164703 has 2 divisors, whose sum is σ = 98942164704. Its totient is φ = 98942164702.

The previous prime is 98942164613. The next prime is 98942164721. The reversal of 98942164703 is 30746124989.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 98942164703 - 218 = 98941902559 is a prime.

It is a super-2 number, since 2×989421647032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (98942164903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49471082351 + 49471082352.

It is an arithmetic number, because the mean of its divisors is an integer number (49471082352).

Almost surely, 298942164703 is an apocalyptic number.

98942164703 is a deficient number, since it is larger than the sum of its proper divisors (1).

98942164703 is an equidigital number, since it uses as much as digits as its factorization.

98942164703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2612736, while the sum is 53.

The spelling of 98942164703 in words is "ninety-eight billion, nine hundred forty-two million, one hundred sixty-four thousand, seven hundred three".