Base | Representation |
---|---|
bin | 10110100000101100111100… |
… | …110011110000010001000100 |
3 | 110222112201102200102212120122 |
4 | 112200230330303300101010 |
5 | 100434041312200340400 |
6 | 550321541443121112 |
7 | 26565553062156665 |
oct | 2640547463602104 |
9 | 428481380385518 |
10 | 99004311340100 |
11 | 29600546794981 |
12 | b12b847673198 |
13 | 43320b313a42a |
14 | 1a63b9720536c |
15 | b6a4e17cc685 |
hex | 5a0b3ccf0444 |
99004311340100 has 18 divisors (see below), whose sum is σ = 214839355608234. Its totient is φ = 39601724536000.
The previous prime is 99004311340087. The next prime is 99004311340147. The reversal of 99004311340100 is 104311340099.
It can be written as a sum of positive squares in 3 ways, for example, as 34653495905284 + 64350815434816 = 5886722^2 + 8021896^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 495021556601 + ... + 495021556800.
It is an arithmetic number, because the mean of its divisors is an integer number (11935519756013).
Almost surely, 299004311340100 is an apocalyptic number.
It is an amenable number.
99004311340100 is an abundant number, since it is smaller than the sum of its proper divisors (115835044268134).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
99004311340100 is a wasteful number, since it uses less digits than its factorization.
99004311340100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 990043113415 (or 990043113408 counting only the distinct ones).
The product of its (nonzero) digits is 11664, while the sum is 35.
Adding to 99004311340100 its reverse (104311340099), we get a palindrome (99108622680199).
The spelling of 99004311340100 in words is "ninety-nine trillion, four billion, three hundred eleven million, three hundred forty thousand, one hundred".
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