Base | Representation |
---|---|
bin | 111011000001100… |
… | …001100110001111 |
3 | 2120000100012011202 |
4 | 323001201212033 |
5 | 4012001134003 |
6 | 242132340115 |
7 | 33353014166 |
oct | 7301414617 |
9 | 2500305152 |
10 | 990255503 |
11 | 468a78686 |
12 | 23777463b |
13 | 12a207a03 |
14 | 957323dd |
15 | 5be09088 |
hex | 3b06198f |
990255503 has 2 divisors, whose sum is σ = 990255504. Its totient is φ = 990255502.
The previous prime is 990255467. The next prime is 990255527. The reversal of 990255503 is 305552099.
990255503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (305552099) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 990255503 - 214 = 990239119 is a prime.
It is a super-2 number, since 2×9902555032 = 1961211922443566018, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (990255533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495127751 + 495127752.
It is an arithmetic number, because the mean of its divisors is an integer number (495127752).
Almost surely, 2990255503 is an apocalyptic number.
990255503 is a deficient number, since it is larger than the sum of its proper divisors (1).
990255503 is an equidigital number, since it uses as much as digits as its factorization.
990255503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60750, while the sum is 38.
The square root of 990255503 is about 31468.3253923688. The cubic root of 990255503 is about 996.7412262627.
The spelling of 990255503 in words is "nine hundred ninety million, two hundred fifty-five thousand, five hundred three".
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