Base | Representation |
---|---|
bin | 101110001010011101… |
… | …1110011010101110111 |
3 | 100110212220212121120001 |
4 | 1130110323303111313 |
5 | 3111012140001134 |
6 | 113313041052131 |
7 | 10106445403504 |
oct | 1342473632567 |
9 | 313786777501 |
10 | 99135468919 |
11 | 3905242a103 |
12 | 17268327047 |
13 | 946b6843a6 |
14 | 4b262d84ab |
15 | 28a33b7414 |
hex | 1714ef3577 |
99135468919 has 2 divisors, whose sum is σ = 99135468920. Its totient is φ = 99135468918.
The previous prime is 99135468911. The next prime is 99135468953. The reversal of 99135468919 is 91986453199.
It is a weak prime.
It is an emirp because it is prime and its reverse (91986453199) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 99135468919 - 23 = 99135468911 is a prime.
It is a super-2 number, since 2×991354689192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (99135468911) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49567734459 + 49567734460.
It is an arithmetic number, because the mean of its divisors is an integer number (49567734460).
Almost surely, 299135468919 is an apocalyptic number.
99135468919 is a deficient number, since it is larger than the sum of its proper divisors (1).
99135468919 is an equidigital number, since it uses as much as digits as its factorization.
99135468919 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18895680, while the sum is 64.
The spelling of 99135468919 in words is "ninety-nine billion, one hundred thirty-five million, four hundred sixty-eight thousand, nine hundred nineteen".
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