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9926486844013 is a prime number
BaseRepresentation
bin1001000001110011000010…
…1110001110001001101101
31022010221222221020222221101
42100130300232032021231
52300113421113002023
633040055355003101
72043110412002335
oct220346056161155
938127887228841
109926486844013
113187888049953
1211439a0439491
135700a9c1935c
14264631ad20c5
151233261c71ad
hex90730b8e26d

9926486844013 has 2 divisors, whose sum is σ = 9926486844014. Its totient is φ = 9926486844012.

The previous prime is 9926486843951. The next prime is 9926486844017. The reversal of 9926486844013 is 3104486846299.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8110574280649 + 1815912563364 = 2847907^2 + 1347558^2 .

It is a cyclic number.

It is not a de Polignac number, because 9926486844013 - 217 = 9926486712941 is a prime.

It is a super-3 number, since 3×99264868440133 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9926486844017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4963243422006 + 4963243422007.

It is an arithmetic number, because the mean of its divisors is an integer number (4963243422007).

Almost surely, 29926486844013 is an apocalyptic number.

It is an amenable number.

9926486844013 is a deficient number, since it is larger than the sum of its proper divisors (1).

9926486844013 is an equidigital number, since it uses as much as digits as its factorization.

9926486844013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 71663616, while the sum is 64.

The spelling of 9926486844013 in words is "nine trillion, nine hundred twenty-six billion, four hundred eighty-six million, eight hundred forty-four thousand, thirteen".