Base | Representation |
---|---|
bin | 11100111010010001000… |
… | …01011000000011100011 |
3 | 10111222000120002110221102 |
4 | 32131020201120003203 |
5 | 112233342130413321 |
6 | 2040201322545015 |
7 | 131524145665226 |
oct | 16351041300343 |
9 | 3458016073842 |
10 | 993354154211 |
11 | 353308583661 |
12 | 14062836816b |
13 | 72899471903 |
14 | 361159595bd |
15 | 1ac8d0a6c0b |
hex | e7488580e3 |
993354154211 has 2 divisors, whose sum is σ = 993354154212. Its totient is φ = 993354154210.
The previous prime is 993354154193. The next prime is 993354154213. The reversal of 993354154211 is 112451453399.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 993354154211 - 222 = 993349959907 is a prime.
Together with 993354154213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (993354154213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496677077105 + 496677077106.
It is an arithmetic number, because the mean of its divisors is an integer number (496677077106).
Almost surely, 2993354154211 is an apocalyptic number.
993354154211 is a deficient number, since it is larger than the sum of its proper divisors (1).
993354154211 is an equidigital number, since it uses as much as digits as its factorization.
993354154211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 583200, while the sum is 47.
The spelling of 993354154211 in words is "nine hundred ninety-three billion, three hundred fifty-four million, one hundred fifty-four thousand, two hundred eleven".
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