Base | Representation |
---|---|
bin | 10010100001001011… |
… | …00011100110000001 |
3 | 221122212112202002101 |
4 | 21100211203212001 |
5 | 130330120110433 |
6 | 4322310350401 |
7 | 501241145233 |
oct | 112045434601 |
9 | 27585482071 |
10 | 9941956993 |
11 | 4241a80491 |
12 | 1b1565b401 |
13 | c259771b7 |
14 | 6a4574253 |
15 | 3d2c4507d |
hex | 250963981 |
9941956993 has 2 divisors, whose sum is σ = 9941956994. Its totient is φ = 9941956992.
The previous prime is 9941956991. The next prime is 9941957071. The reversal of 9941956993 is 3996591499.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6530579344 + 3411377649 = 80812^2 + 58407^2 .
It is a cyclic number.
It is not a de Polignac number, because 9941956993 - 21 = 9941956991 is a prime.
Together with 9941956991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (9941956991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4970978496 + 4970978497.
It is an arithmetic number, because the mean of its divisors is an integer number (4970978497).
Almost surely, 29941956993 is an apocalyptic number.
It is an amenable number.
9941956993 is a deficient number, since it is larger than the sum of its proper divisors (1).
9941956993 is an equidigital number, since it uses as much as digits as its factorization.
9941956993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21257640, while the sum is 64.
The square root of 9941956993 is about 99709.3626145509. The cubic root of 9941956993 is about 2150.2582702538.
The spelling of 9941956993 in words is "nine billion, nine hundred forty-one million, nine hundred fifty-six thousand, nine hundred ninety-three".
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