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995031114760031 is a prime number
BaseRepresentation
bin1110001000111110011011110…
…0001000101011111101011111
311211111010001020012221202002112
43202033212330020223331133
52020410042210334310111
613444130552244144235
7416405424420435416
oct34217467410537537
94744101205852075
10995031114760031
11269058364968898
129372384309807b
133392a0542a651b
141379da9763a47d
157a08099502e8b
hex388f9bc22bf5f

995031114760031 has 2 divisors, whose sum is σ = 995031114760032. Its totient is φ = 995031114760030.

The previous prime is 995031114760027. The next prime is 995031114760037. The reversal of 995031114760031 is 130067411130599.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 995031114760031 - 22 = 995031114760027 is a prime.

It is a super-2 number, since 2×9950311147600312 (a number of 31 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (995031114760037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497515557380015 + 497515557380016.

It is an arithmetic number, because the mean of its divisors is an integer number (497515557380016).

Almost surely, 2995031114760031 is an apocalyptic number.

995031114760031 is a deficient number, since it is larger than the sum of its proper divisors (1).

995031114760031 is an equidigital number, since it uses as much as digits as its factorization.

995031114760031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 612360, while the sum is 50.

The spelling of 995031114760031 in words is "nine hundred ninety-five trillion, thirty-one billion, one hundred fourteen million, seven hundred sixty thousand, thirty-one".