Base | Representation |
---|---|
bin | 11100111110001001000… |
… | …01001100010101011111 |
3 | 10112011101112121000210102 |
4 | 32133010201030111133 |
5 | 112302122211342431 |
6 | 2041143555331315 |
7 | 131626536323666 |
oct | 16370441142537 |
9 | 3464345530712 |
10 | 995434480991 |
11 | 3541858a4995 |
12 | 140b08bb0b3b |
13 | 72b3b461cc2 |
14 | 36271d63ddd |
15 | 1ad60a34dcb |
hex | e7c484c55f |
995434480991 has 2 divisors, whose sum is σ = 995434480992. Its totient is φ = 995434480990.
The previous prime is 995434480967. The next prime is 995434480993. The reversal of 995434480991 is 199084434599.
It is a strong prime.
It is an emirp because it is prime and its reverse (199084434599) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 995434480991 - 218 = 995434218847 is a prime.
Together with 995434480993, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (995434480993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497717240495 + 497717240496.
It is an arithmetic number, because the mean of its divisors is an integer number (497717240496).
Almost surely, 2995434480991 is an apocalyptic number.
995434480991 is a deficient number, since it is larger than the sum of its proper divisors (1).
995434480991 is an equidigital number, since it uses as much as digits as its factorization.
995434480991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50388480, while the sum is 65.
The spelling of 995434480991 in words is "nine hundred ninety-five billion, four hundred thirty-four million, four hundred eighty thousand, nine hundred ninety-one".
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