100004141 has 2 divisors, whose sum is σ = 100004142. Its totient is φ = 100004140.

The previous prime is 100004137. The next prime is 100004143. The reversal of 100004141 is 141400001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51423241 + 48580900 = 7171^2 + 6970^2 .

It is an emirp because it is prime and its reverse (141400001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100004141 - 2² = 100004137 is a prime.

It is a super-3 number, since 3×100004141³ (a number of 25 digits) contains 333 as substring.

It is a Sophie Germain prime.

Together with 100004143, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100004143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50002070 + 50002071.

It is an arithmetic number, because the mean of its divisors is an integer number (50002071).

Almost surely, 2^100004141 is an apocalyptic number.

It is an amenable number.

100004141 is a deficient number, since it is larger than the sum of its proper divisors (1).

100004141 is an equidigital number, since it uses as much as digits as its factorization.

100004141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 11.

The square root of 100004141 is about 10000.2070478566. The cubic root of 100004141 is about 464.1652902126.

Adding to 100004141 its reverse (141400001), we get a palindrome (241404142).

It can be divided in two parts, 10000 and 4141, that added together give a palindrome (14141).

The spelling of 100004141 in words is "one hundred million, four thousand, one hundred forty-one".