100012101020021 has 2 divisors, whose sum is σ = 100012101020022. Its totient is φ = 100012101020020.

The previous prime is 100012101019991. The next prime is 100012101020023. The reversal of 100012101020021 is 120020101210001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83810179944100 + 16201921075921 = 9154790^2 + 4025161^2 .

It is a cyclic number.

It is not a de Polignac number, because 100012101020021 - 2¹⁴ = 100012101003637 is a prime.

It is a super-3 number, since 3×100012101020021³ (a number of 43 digits) contains 333 as substring.

Together with 100012101020023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100012101019984 and 100012101020011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100012101020023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006050510010 + 50006050510011.

It is an arithmetic number, because the mean of its divisors is an integer number (50006050510011).

Almost surely, 2^{100012101020021} is an apocalyptic number.

It is an amenable number.

100012101020021 is a deficient number, since it is larger than the sum of its proper divisors (1).

100012101020021 is an equidigital number, since it uses as much as digits as its factorization.

100012101020021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 100012101020021 its reverse (120020101210001), we get a palindrome (220032202230022).

The spelling of 100012101020021 in words is "one hundred trillion, twelve billion, one hundred one million, twenty thousand, twenty-one".