Base | Representation |
---|---|
bin | 101110100100101010… |
… | …0011100010010011000 |
3 | 100120011011122001120210 |
4 | 1131021110130102120 |
5 | 3114312132441240 |
6 | 113540154251120 |
7 | 10140306614523 |
oct | 1351124342230 |
9 | 316134561523 |
10 | 100014343320 |
11 | 39463542491 |
12 | 17472726aa0 |
13 | 957b792208 |
14 | 4baad15bba |
15 | 290561e780 |
hex | 174951c498 |
100014343320 has 128 divisors (see below), whose sum is σ = 308303697600. Its totient is φ = 25936920576.
The previous prime is 100014343313. The next prime is 100014343321. The reversal of 100014343320 is 23343410001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100014343321) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11934972 + ... + 11943348.
Almost surely, 2100014343320 is an apocalyptic number.
100014343320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 100014343320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154151848800).
100014343320 is an abundant number, since it is smaller than the sum of its proper divisors (208289354280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100014343320 is a wasteful number, since it uses less digits than its factorization.
100014343320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11117 (or 11113 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 100014343320 its reverse (23343410001), we get a palindrome (123357753321).
The spelling of 100014343320 in words is "one hundred billion, fourteen million, three hundred forty-three thousand, three hundred twenty".
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