1000341413 has 2 divisors, whose sum is σ = 1000341414. Its totient is φ = 1000341412.

The previous prime is 1000341389. The next prime is 1000341437. The reversal of 1000341413 is 3141430001.

It is a balanced prime because it is at equal distance from previous prime (1000341389) and next prime (1000341437).

It can be written as a sum of positive squares in only one way, i.e., 870427009 + 129914404 = 29503^2 + 11398^2 .

It is an emirp because it is prime and its reverse (3141430001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000341413 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000341391 and 1000341400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000341443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500170706 + 500170707.

It is an arithmetic number, because the mean of its divisors is an integer number (500170707).

Almost surely, 2^1000341413 is an apocalyptic number.

It is an amenable number.

1000341413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000341413 is an equidigital number, since it uses as much as digits as its factorization.

1000341413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1000341413 is about 31628.1743545213. The cubic root of 1000341413 is about 1000.1137913844.

Adding to 1000341413 its reverse (3141430001), we get a palindrome (4141771414).

The spelling of 1000341413 in words is "one billion, three hundred forty-one thousand, four hundred thirteen".