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100113001301 = 238235288869
BaseRepresentation
bin101110100111100110…
…0110010101101010101
3100120102001021101220002
41131033030302231111
53120012412020201
6113554041021045
710142615320235
oct1351714625525
9316361241802
10100113001301
11395041a7705
121749b784785
139596055c11
144bba077cc5
15290e10b76b
hex174f332b55

100113001301 has 8 divisors (see below), whose sum is σ = 104592693120. Its totient is φ = 95643888912.

The previous prime is 100113001277. The next prime is 100113001381. The reversal of 100113001301 is 103100311001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100113001301 is a prime.

It is a super-2 number, since 2×1001130013012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100113001381) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2625506 + ... + 2663363.

It is an arithmetic number, because the mean of its divisors is an integer number (13074086640).

Almost surely, 2100113001301 is an apocalyptic number.

It is an amenable number.

100113001301 is a deficient number, since it is larger than the sum of its proper divisors (4479691819).

100113001301 is an equidigital number, since it uses as much as digits as its factorization.

100113001301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5289715.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 100113001301 its reverse (103100311001), we get a palindrome (203213312302).

The spelling of 100113001301 in words is "one hundred billion, one hundred thirteen million, one thousand, three hundred one".

Divisors: 1 23 823 18929 5288869 121643987 4352739187 100113001301