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100132301112 = 2334172179213
BaseRepresentation
bin101110101000001011…
…0011010100100111000
3100120110101120221020220
41131100112122210320
53120032332113422
6114000010420040
710143241342014
oct1352026324470
9316411527226
10100132301112
1139514089968
12174a6131620
13959a05271c
144bbc85d544
152910b6ee5c
hex175059a938

100132301112 has 16 divisors (see below), whose sum is σ = 250330752840. Its totient is φ = 33377433696.

The previous prime is 100132301083. The next prime is 100132301197. The reversal of 100132301112 is 211103231001.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 100132301091 and 100132301100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2086089583 + ... + 2086089630.

Almost surely, 2100132301112 is an apocalyptic number.

100132301112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

100132301112 is an abundant number, since it is smaller than the sum of its proper divisors (150198451728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100132301112 is a wasteful number, since it uses less digits than its factorization.

100132301112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4172179222 (or 4172179218 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 100132301112 its reverse (211103231001), we get a palindrome (311235532113).

The spelling of 100132301112 in words is "one hundred billion, one hundred thirty-two million, three hundred one thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 12 24 4172179213 8344358426 12516537639 16688716852 25033075278 33377433704 50066150556 100132301112