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100133000131 is a prime number
BaseRepresentation
bin101110101000001100…
…1000101001111000011
3100120110102220110010111
41131100121011033003
53120033022001011
6114000033412151
710143250312663
oct1352031051703
9316412813114
10100133000131
113951451706a
12174a640a057
13959a238948
144bbc9a21a3
152910c5c121
hex17506453c3

100133000131 has 2 divisors, whose sum is σ = 100133000132. Its totient is φ = 100133000130.

The previous prime is 100133000129. The next prime is 100133000141. The reversal of 100133000131 is 131000331001.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (131000331001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100133000131 - 21 = 100133000129 is a prime.

It is a super-2 number, since 2×1001330001312 (a number of 23 digits) contains 22 as substring.

Together with 100133000129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (100133000111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066500065 + 50066500066.

It is an arithmetic number, because the mean of its divisors is an integer number (50066500066).

Almost surely, 2100133000131 is an apocalyptic number.

100133000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100133000131 is an equidigital number, since it uses as much as digits as its factorization.

100133000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 100133000131 its reverse (131000331001), we get a palindrome (231133331132).

The spelling of 100133000131 in words is "one hundred billion, one hundred thirty-three million, one hundred thirty-one", and thus it is an aban number.