100200100211117 has 2 divisors, whose sum is σ = 100200100211118. Its totient is φ = 100200100211116.

The previous prime is 100200100211053. The next prime is 100200100211119. The reversal of 100200100211117 is 711112001002001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98887531296841 + 1312568914276 = 9944221^2 + 1145674^2 .

It is a cyclic number.

It is not a de Polignac number, because 100200100211117 - 2⁶ = 100200100211053 is a prime.

Together with 100200100211119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100200100211095 and 100200100211104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100200100211119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100050105558 + 50100050105559.

It is an arithmetic number, because the mean of its divisors is an integer number (50100050105559).

Almost surely, 2^{100200100211117} is an apocalyptic number.

It is an amenable number.

100200100211117 is a deficient number, since it is larger than the sum of its proper divisors (1).

100200100211117 is an equidigital number, since it uses as much as digits as its factorization.

100200100211117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 100200100211117 its reverse (711112001002001), we get a palindrome (811312101213118).

The spelling of 100200100211117 in words is "one hundred trillion, two hundred billion, one hundred million, two hundred eleven thousand, one hundred seventeen".