100231211121120 has 384 divisors, whose sum is σ = 376030840510080. Its totient is φ = 25156067180544.

The previous prime is 100231211121073. The next prime is 100231211121133. The reversal of 100231211121120 is 21121112132001.

It is a happy number.

100231211121120 is a `hidden beast` number, since 10 + 0 + 2 + 312 + 111 + 211 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 100231211121093 and 100231211121102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2476077 + ... + 14373356.

It is an arithmetic number, because the mean of its divisors is an integer number (979246980495).

Almost surely, 2^{100231211121120} is an apocalyptic number.

100231211121120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100231211121120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (188015420255040).

100231211121120 is an abundant number, since it is smaller than the sum of its proper divisors (275799629388960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100231211121120 is an equidigital number, since it uses as much as digits as its factorization.

100231211121120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16849486 (or 16849460 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 100231211121120 its reverse (21121112132001), we get a palindrome (121352323253121).

The spelling of 100231211121120 in words is "one hundred trillion, two hundred thirty-one billion, two hundred eleven million, one hundred twenty-one thousand, one hundred twenty".