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10024411217 is a prime number
BaseRepresentation
bin10010101011000000…
…00110000001010001
3221212121200212000112
421111200012001101
5131012222124332
64334413531105
7503262042452
oct112540060121
927777625015
1010024411217
114284578577
121b391a3a95
13c39a86692
146b14b9129
153da0d0db2
hex255806051

10024411217 has 2 divisors, whose sum is σ = 10024411218. Its totient is φ = 10024411216.

The previous prime is 10024411207. The next prime is 10024411219. The reversal of 10024411217 is 71211442001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8725241281 + 1299169936 = 93409^2 + 36044^2 .

It is a cyclic number.

It is not a de Polignac number, because 10024411217 - 214 = 10024394833 is a prime.

Together with 10024411219, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10024411192 and 10024411201.

It is not a weakly prime, because it can be changed into another prime (10024411219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012205608 + 5012205609.

It is an arithmetic number, because the mean of its divisors is an integer number (5012205609).

Almost surely, 210024411217 is an apocalyptic number.

It is an amenable number.

10024411217 is a deficient number, since it is larger than the sum of its proper divisors (1).

10024411217 is an equidigital number, since it uses as much as digits as its factorization.

10024411217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 10024411217 its reverse (71211442001), we get a palindrome (81235853218).

The spelling of 10024411217 in words is "ten billion, twenty-four million, four hundred eleven thousand, two hundred seventeen".