100331012141 has 2 divisors, whose sum is σ = 100331012142. Its totient is φ = 100331012140.

The previous prime is 100331012129. The next prime is 100331012143. The reversal of 100331012141 is 141210133001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70731530116 + 29599482025 = 265954^2 + 172045^2 .

It is a cyclic number.

It is not a de Polignac number, because 100331012141 - 2¹⁴ = 100330995757 is a prime.

Together with 100331012143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100331012143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50165506070 + 50165506071.

It is an arithmetic number, because the mean of its divisors is an integer number (50165506071).

Almost surely, 2^100331012141 is an apocalyptic number.

It is an amenable number.

100331012141 is a deficient number, since it is larger than the sum of its proper divisors (1).

100331012141 is an equidigital number, since it uses as much as digits as its factorization.

100331012141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 100331012141 its reverse (141210133001), we get a palindrome (241541145142).

The spelling of 100331012141 in words is "one hundred billion, three hundred thirty-one million, twelve thousand, one hundred forty-one".