Base | Representation |
---|---|
bin | 101110110000100011… |
… | …0111011000100001011 |
3 | 100121011222121220112022 |
4 | 1131201012323010023 |
5 | 3121121320440210 |
6 | 114043532435055 |
7 | 10153224156353 |
oct | 1354106730413 |
9 | 317158556468 |
10 | 100413452555 |
11 | 3964885a129 |
12 | 17564318a8b |
13 | 9613381220 |
14 | 4c07d27b63 |
15 | 292a6a9155 |
hex | 17611bb10b |
100413452555 has 64 divisors (see below), whose sum is σ = 136941235200. Its totient is φ = 70128115200.
The previous prime is 100413452501. The next prime is 100413452593. The reversal of 100413452555 is 555254314001.
It is not a de Polignac number, because 100413452555 - 210 = 100413451531 is a prime.
It is a super-2 number, since 2×1004134525552 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 64823921 + ... + 64825469.
It is an arithmetic number, because the mean of its divisors is an integer number (2139706800).
Almost surely, 2100413452555 is an apocalyptic number.
100413452555 is a deficient number, since it is larger than the sum of its proper divisors (36527782645).
100413452555 is a wasteful number, since it uses less digits than its factorization.
100413452555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2052.
The product of its (nonzero) digits is 60000, while the sum is 35.
Adding to 100413452555 its reverse (555254314001), we get a palindrome (655667766556).
The spelling of 100413452555 in words is "one hundred billion, four hundred thirteen million, four hundred fifty-two thousand, five hundred fifty-five".
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