10051101101141 has 2 divisors, whose sum is σ = 10051101101142. Its totient is φ = 10051101101140.

The previous prime is 10051101101059. The next prime is 10051101101143. The reversal of 10051101101141 is 14110110115001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10050985968241 + 115132900 = 3170329^2 + 10730^2 .

It is a cyclic number.

It is not a de Polignac number, because 10051101101141 - 2¹⁸ = 10051100838997 is a prime.

Together with 10051101101143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10051101101143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5025550550570 + 5025550550571.

It is an arithmetic number, because the mean of its divisors is an integer number (5025550550571).

Almost surely, 2^{10051101101141} is an apocalyptic number.

It is an amenable number.

10051101101141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10051101101141 is an equidigital number, since it uses as much as digits as its factorization.

10051101101141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20, while the sum is 17.

Adding to 10051101101141 its reverse (14110110115001), we get a palindrome (24161211216142).

The spelling of 10051101101141 in words is "ten trillion, fifty-one billion, one hundred one million, one hundred one thousand, one hundred forty-one".