101010132213003 has 64 divisors (see below), whose sum is σ = 163431641640960. Its totient is φ = 61282308931200.

The previous prime is 101010132212999. The next prime is 101010132213131. The reversal of 101010132213003 is 300312231010101.

It is not a de Polignac number, because 101010132213003 - 2² = 101010132212999 is a prime.

It is a super-3 number, since 3×101010132213003³ (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (101010132214003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 873497998 + ... + 873613628.

It is an arithmetic number, because the mean of its divisors is an integer number (2553619400640).

Almost surely, 2^{101010132213003} is an apocalyptic number.

101010132213003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

101010132213003 is a deficient number, since it is larger than the sum of its proper divisors (62421509427957).

101010132213003 is a wasteful number, since it uses less digits than its factorization.

101010132213003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150777 (or 150771 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 101010132213003 its reverse (300312231010101), we get a palindrome (401322363223104).

The spelling of 101010132213003 in words is "one hundred one trillion, ten billion, one hundred thirty-two million, two hundred thirteen thousand, three".