10110113311 has 2 divisors, whose sum is σ = 10110113312. Its totient is φ = 10110113310.

The previous prime is 10110113309. The next prime is 10110113329. The reversal of 10110113311 is 11331101101.

10110113311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10110113311 - 2¹ = 10110113309 is a prime.

It is a super-2 number, since 2×10110113311² (a number of 21 digits) contains 22 as substring.

Together with 10110113309, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10110113291 and 10110113300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110116311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055056655 + 5055056656.

It is an arithmetic number, because the mean of its divisors is an integer number (5055056656).

Almost surely, 2^10110113311 is an apocalyptic number.

10110113311 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110113311 is an equidigital number, since it uses as much as digits as its factorization.

10110113311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 10110113311 its reverse (11331101101), we get a palindrome (21441214412).

The spelling of 10110113311 in words is "ten billion, one hundred ten million, one hundred thirteen thousand, three hundred eleven".