10110213119 has 2 divisors, whose sum is σ = 10110213120. Its totient is φ = 10110213118.

The previous prime is 10110213107. The next prime is 10110213121. The reversal of 10110213119 is 91131201101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10110213119 - 2⁴ = 10110213103 is a prime.

It is a super-2 number, since 2×10110213119² (a number of 21 digits) contains 22 as substring.

Together with 10110213121, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10110213119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110213149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055106559 + 5055106560.

It is an arithmetic number, because the mean of its divisors is an integer number (5055106560).

Almost surely, 2^10110213119 is an apocalyptic number.

10110213119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110213119 is an equidigital number, since it uses as much as digits as its factorization.

10110213119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 20.

The spelling of 10110213119 in words is "ten billion, one hundred ten million, two hundred thirteen thousand, one hundred nineteen".