10111022147 has 2 divisors, whose sum is σ = 10111022148. Its totient is φ = 10111022146.

The previous prime is 10111022087. The next prime is 10111022149. The reversal of 10111022147 is 74122011101.

10111022147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10111022147 - 2²⁶ = 10043913283 is a prime.

It is a super-3 number, since 3×10111022147³ (a number of 31 digits) contains 333 as substring.

Together with 10111022149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10111022149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055511073 + 5055511074.

It is an arithmetic number, because the mean of its divisors is an integer number (5055511074).

Almost surely, 2^10111022147 is an apocalyptic number.

10111022147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111022147 is an equidigital number, since it uses as much as digits as its factorization.

10111022147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 10111022147 its reverse (74122011101), we get a palindrome (84233033248).

The spelling of 10111022147 in words is "ten billion, one hundred eleven million, twenty-two thousand, one hundred forty-seven".