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101112121102 = 250556060551
BaseRepresentation
bin101111000101011000…
…0001000011100001110
3100122222200021221121011
41132022300020130032
53124034200333402
6114241131355434
710206436564036
oct1361260103416
9318880257534
10101112121102
113997717a153
121771a2b2b7a
1396c5045575
144c72a368c6
15296bbb6ed7
hex178ac0870e

101112121102 has 4 divisors (see below), whose sum is σ = 151668181656. Its totient is φ = 50556060550.

The previous prime is 101112121091. The next prime is 101112121109. The reversal of 101112121102 is 201121211101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 201121211101 = 225223892987.

It is a super-3 number, since 3×1011121211023 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101112121109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25278030274 + ... + 25278030277.

It is an arithmetic number, because the mean of its divisors is an integer number (37917045414).

Almost surely, 2101112121102 is an apocalyptic number.

101112121102 is a deficient number, since it is larger than the sum of its proper divisors (50556060554).

101112121102 is an equidigital number, since it uses as much as digits as its factorization.

101112121102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50556060553.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 101112121102 its reverse (201121211101), we get a palindrome (302233332203).

The spelling of 101112121102 in words is "one hundred one billion, one hundred twelve million, one hundred twenty-one thousand, one hundred two".

Divisors: 1 2 50556060551 101112121102