Base | Representation |
---|---|
bin | 11101011011010111000… |
… | …01101101010011101000 |
3 | 10120122212210010122212112 |
4 | 32231223201231103220 |
5 | 113031234024004000 |
6 | 2052300330501452 |
7 | 133023346232051 |
oct | 16555341552350 |
9 | 3518783118775 |
10 | 1011121313000 |
11 | 35a8a5691a67 |
12 | 143b66594888 |
13 | 7446b389916 |
14 | 36d1d495728 |
15 | 1b47ccba235 |
hex | eb6b86d4e8 |
1011121313000 has 64 divisors (see below), whose sum is σ = 2372367975120. Its totient is φ = 403364064000.
The previous prime is 1011121312987. The next prime is 1011121313003. The reversal of 1011121313000 is 3131211101.
It is a happy number.
It can be written as a sum of positive squares in 8 ways, for example, as 1027971844 + 1010093341156 = 32062^2 + 1005034^2 .
It is not an unprimeable number, because it can be changed into a prime (1011121313003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 982391 + ... + 1728390.
Almost surely, 21011121313000 is an apocalyptic number.
1011121313000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1011121313000 is an abundant number, since it is smaller than the sum of its proper divisors (1361246662120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1011121313000 is a wasteful number, since it uses less digits than its factorization.
1011121313000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2711175 (or 2711161 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 1011121313000 its reverse (3131211101), we get a palindrome (1014252524101).
The spelling of 1011121313000 in words is "one trillion, eleven billion, one hundred twenty-one million, three hundred thirteen thousand".
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