10111220221301 has 2 divisors, whose sum is σ = 10111220221302. Its totient is φ = 10111220221300.

The previous prime is 10111220221217. The next prime is 10111220221303. The reversal of 10111220221301 is 10312202211101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7132109701201 + 2979110520100 = 2670601^2 + 1726010^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10111220221301 is a prime.

Together with 10111220221303, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10111220221301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111220221303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055610110650 + 5055610110651.

It is an arithmetic number, because the mean of its divisors is an integer number (5055610110651).

Almost surely, 2^{10111220221301} is an apocalyptic number.

It is an amenable number.

10111220221301 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111220221301 is an equidigital number, since it uses as much as digits as its factorization.

10111220221301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10111220221301 its reverse (10312202211101), we get a palindrome (20423422432402).

The spelling of 10111220221301 in words is "ten trillion, one hundred eleven billion, two hundred twenty million, two hundred twenty-one thousand, three hundred one".