10112212111 has 2 divisors, whose sum is σ = 10112212112. Its totient is φ = 10112212110.

The previous prime is 10112212067. The next prime is 10112212127. The reversal of 10112212111 is 11121221101.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (11121221101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10112212111 - 2¹¹ = 10112210063 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112212091 and 10112212100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112212141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056106055 + 5056106056.

It is an arithmetic number, because the mean of its divisors is an integer number (5056106056).

Almost surely, 2^10112212111 is an apocalyptic number.

10112212111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112212111 is an equidigital number, since it uses as much as digits as its factorization.

10112212111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 10112212111 its reverse (11121221101), we get a palindrome (21233433212).

It can be divided in two parts, 1011 and 2212111, that added together give a palindrome (2213122).

The spelling of 10112212111 in words is "ten billion, one hundred twelve million, two hundred twelve thousand, one hundred eleven".