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101133000335 = 5101200263367
BaseRepresentation
bin101111000101111111…
…1110001111010001111
3100200001010120201112002
41132023333301322033
53124110022002320
6114243155102515
710210112214323
oct1361377617217
9320033521462
10101133000335
1139987a40014
12177252a1a3b
1396c9475c43
144c7570d983
15296d93d675
hex178bff1e8f

101133000335 has 8 divisors (see below), whose sum is σ = 122561181216. Its totient is φ = 80105346400.

The previous prime is 101133000317. The next prime is 101133000433. The reversal of 101133000335 is 533000331101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101133000335 - 28 = 101133000079 is a prime.

It is a super-2 number, since 2×1011330003352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100131179 + ... + 100132188.

It is an arithmetic number, because the mean of its divisors is an integer number (15320147652).

Almost surely, 2101133000335 is an apocalyptic number.

101133000335 is a deficient number, since it is larger than the sum of its proper divisors (21428180881).

101133000335 is a wasteful number, since it uses less digits than its factorization.

101133000335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200263473.

The product of its (nonzero) digits is 405, while the sum is 20.

Adding to 101133000335 its reverse (533000331101), we get a palindrome (634133331436).

The spelling of 101133000335 in words is "one hundred one billion, one hundred thirty-three million, three hundred thirty-five", and thus it is an aban number.

Divisors: 1 5 101 505 200263367 1001316835 20226600067 101133000335