Base | Representation |
---|---|
bin | 101111000110100100… |
… | …1111010001111100101 |
3 | 100200002111011000022001 |
4 | 1132031021322033211 |
5 | 3124130010330000 |
6 | 114245131405301 |
7 | 10210436331562 |
oct | 1361511721745 |
9 | 320074130261 |
10 | 101152433125 |
11 | 39997a03177 |
12 | 1772b8b3831 |
13 | 97004bb133 |
14 | 4c7812b869 |
15 | 29704cb46a |
hex | 178d27a3e5 |
101152433125 has 40 divisors (see below), whose sum is σ = 139654646208. Its totient is φ = 72850272000.
The previous prime is 101152433119. The next prime is 101152433183. The reversal of 101152433125 is 521334251101.
It is not a de Polignac number, because 101152433125 - 23 = 101152433117 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 101152433093 and 101152433102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 37414 + ... + 451336.
Almost surely, 2101152433125 is an apocalyptic number.
It is an amenable number.
101152433125 is a deficient number, since it is larger than the sum of its proper divisors (38502213083).
101152433125 is an equidigital number, since it uses as much as digits as its factorization.
101152433125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 413983 (or 413968 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 101152433125 its reverse (521334251101), we get a palindrome (622486684226).
The spelling of 101152433125 in words is "one hundred one billion, one hundred fifty-two million, four hundred thirty-three thousand, one hundred twenty-five".
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