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1012019117 is a prime number
BaseRepresentation
bin111100010100100…
…010111110101101
32121112021220020112
4330110202332231
54033034102432
6244231025405
734036010024
oct7424427655
92545256215
101012019117
1147a292a3a
12242b0b265
13131887aa5
14985998bb
155dca77b2
hex3c522fad

1012019117 has 2 divisors, whose sum is σ = 1012019118. Its totient is φ = 1012019116.

The previous prime is 1012019069. The next prime is 1012019123. The reversal of 1012019117 is 7119102101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 930189001 + 81830116 = 30499^2 + 9046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1012019117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1012019092 and 1012019101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012013117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506009558 + 506009559.

It is an arithmetic number, because the mean of its divisors is an integer number (506009559).

Almost surely, 21012019117 is an apocalyptic number.

It is an amenable number.

1012019117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012019117 is an equidigital number, since it uses as much as digits as its factorization.

1012019117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 23.

The square root of 1012019117 is about 31812.2479086279. The cubic root of 1012019117 is about 1003.9904276400.

The spelling of 1012019117 in words is "one billion, twelve million, nineteen thousand, one hundred seventeen".