10121110001141 has 2 divisors, whose sum is σ = 10121110001142. Its totient is φ = 10121110001140.

The previous prime is 10121110001087. The next prime is 10121110001143. The reversal of 10121110001141 is 14110001112101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9809868749041 + 311241252100 = 3132071^2 + 557890^2 .

It is a cyclic number.

It is not a de Polignac number, because 10121110001141 - 2⁶ = 10121110001077 is a prime.

Together with 10121110001143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10121110001143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060555000570 + 5060555000571.

It is an arithmetic number, because the mean of its divisors is an integer number (5060555000571).

Almost surely, 2^{10121110001141} is an apocalyptic number.

It is an amenable number.

10121110001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10121110001141 is an equidigital number, since it uses as much as digits as its factorization.

10121110001141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 10121110001141 its reverse (14110001112101), we get a palindrome (24231111113242).

The spelling of 10121110001141 in words is "ten trillion, one hundred twenty-one billion, one hundred ten million, one thousand, one hundred forty-one".