Base | Representation |
---|---|
bin | 10010110110101010… |
… | …01011001100100101 |
3 | 222010102201122122200 |
4 | 21123111023030211 |
5 | 131212241242013 |
6 | 4352230045113 |
7 | 505560245355 |
oct | 113325131445 |
9 | 28112648580 |
10 | 10122212133 |
11 | 43247a7880 |
12 | 1b65aa9799 |
13 | c5410a247 |
14 | 6c0496b65 |
15 | 3e399de73 |
hex | 25b54b325 |
10122212133 has 24 divisors (see below), whose sum is σ = 16789637280. Its totient is φ = 5811795360.
The previous prime is 10122212099. The next prime is 10122212197. The reversal of 10122212133 is 33121222101.
10122212133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10122212133 - 26 = 10122212069 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10122212033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2688766 + ... + 2692527.
It is an arithmetic number, because the mean of its divisors is an integer number (699568220).
Almost surely, 210122212133 is an apocalyptic number.
It is an amenable number.
10122212133 is a deficient number, since it is larger than the sum of its proper divisors (6667425147).
10122212133 is a wasteful number, since it uses less digits than its factorization.
10122212133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5381329 (or 5381326 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 10122212133 its reverse (33121222101), we get a palindrome (43243434234).
The spelling of 10122212133 in words is "ten billion, one hundred twenty-two million, two hundred twelve thousand, one hundred thirty-three".
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