Base | Representation |
---|---|
bin | 11101011101011010010… |
… | …00100010111010110111 |
3 | 10120202201111022000120022 |
4 | 32232231020202322313 |
5 | 113041012313404421 |
6 | 2053001450355355 |
7 | 133062543102221 |
oct | 16565510427267 |
9 | 3522644260508 |
10 | 1012222013111 |
11 | 36030aa35281 |
12 | 14421312bb5b |
13 | 745b542416a |
14 | 36dc5737411 |
15 | 1b4e473d7ab |
hex | ebad222eb7 |
1012222013111 has 2 divisors, whose sum is σ = 1012222013112. Its totient is φ = 1012222013110.
The previous prime is 1012222013087. The next prime is 1012222013123. The reversal of 1012222013111 is 1113102222101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1012222013111 - 238 = 737344106167 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1012222013111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012222013711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506111006555 + 506111006556.
It is an arithmetic number, because the mean of its divisors is an integer number (506111006556).
Almost surely, 21012222013111 is an apocalyptic number.
1012222013111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012222013111 is an equidigital number, since it uses as much as digits as its factorization.
1012222013111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1012222013111 its reverse (1113102222101), we get a palindrome (2125324235212).
The spelling of 1012222013111 in words is "one trillion, twelve billion, two hundred twenty-two million, thirteen thousand, one hundred eleven".
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