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10132433 is a prime number
BaseRepresentation
bin100110101001…
…101111010001
3201001210002022
4212221233101
510043214213
61001101225
7152060423
oct46515721
921053068
1010132433
1157a0713
123487815
132139c2c
1414ba813
15d52308
hex9a9bd1

10132433 has 2 divisors, whose sum is σ = 10132434. Its totient is φ = 10132432.

The previous prime is 10132427. The next prime is 10132439. The reversal of 10132433 is 33423101.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (10132427) and next prime (10132439).

It can be written as a sum of positive squares in only one way, i.e., 7006609 + 3125824 = 2647^2 + 1768^2 .

It is an emirp because it is prime and its reverse (33423101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10132433 - 24 = 10132417 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10132439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066216 + 5066217.

It is an arithmetic number, because the mean of its divisors is an integer number (5066217).

Almost surely, 210132433 is an apocalyptic number.

It is an amenable number.

10132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10132433 is an equidigital number, since it uses as much as digits as its factorization.

10132433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 17.

The square root of 10132433 is about 3183.1482843248. The cubic root of 10132433 is about 216.3903620587.

Adding to 10132433 its reverse (33423101), we get a palindrome (43555534).

The spelling of 10132433 in words is "ten million, one hundred thirty-two thousand, four hundred thirty-three".